HW6-phy2048-Spring-2014-solution

Which yields v 12 m s the second part involves either

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: P46. Our +x direction is east and +y direction is north. The linear momenta for the two m = 2.0 kg parts are then ! ! p1 = mv1 = mv1 " j where v1 = 3.0 m/s, and ! ! p2 = mv2 = m v2 x ˆ + v2y ˆ = mv2 cosθ ˆ + sinθ ˆ i j i j ( ) ( ) where v2 = 5.0 m/s and θ = 30°. The combined linear momentum of both parts is then rrr P = p1 + p2 = mv1 ˆ + mv2 cos θ ˆ + sinθ ˆ = ( mv2 cos θ ) ˆ + ( mv1 + mv2 sin θ ) ˆ j i j i j ( ) = ( 2.0 kg ) ( 5.0 m/s ) ( cos 30° ) ˆ + ( 2.0 kg ) (3.0 m/s + (5.0 m/s ) (sin 30° ) ) ˆ i j ( ) = 8.66 ˆ + 11 ˆ kg ⋅ m/s. i j From conservation of linear momentum we know that this is also the linear momentum of the whol...
View Full Document

{[ snackBarMessage ]}

Ask a homework question - tutors are online