HW1-phy2048-Spring-2014-solution

59 m2 121 m2 122 m d the angle between r

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Unformatted text preview: 1.34 m/s2 Since the time interval for the decelerating stage turns out to be the same, we double this result and obtain t = 49.1 s for the travel time between stations. (c) With a “dead time” of 20 s, we have T = t + 20 = 69.1 s for the total time between start- ups. Thus, Eq. 2- 2 gives 806 m vavg = = 11.7 m / s . 69.1 s 2P50. The y coordinate of Apple 1 obeys y – yo1 = – 1 g t2 where y = 0 when t = 2.0 s. This 2 allows us to solve for yo1, and we find yo1 = 19.6 m. The graph for the coordinate of Apple 2 (which is thrown apparently at t = 1.0 s with velocity v2) is y – yo2 = v2(t – 1.0) – 1 g (t – 1.0)2 2 where yo2 = yo1 = 19.6 m and where y = 0 when t = 2.25 s. Thus, we obtain...
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This document was uploaded on 03/24/2014.

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