Unformatted text preview: ⎜
⎟ ⎜ −6 3 ⎟ = 1 × 10 kg m .
⎝ cm ⎠ ⎝ g ⎠ ⎝ 10 m ⎠ Thus, the mass of a cubic meter of water is 1000 kg. (b) We divide the mass of the water by the time taken to drain it. The mass is found from M = ρV (the product of the volume of water and its density): ( )( ) M = 5700 m3 1 × 103 kg m3 = 5.70 × 106 kg. The time is t = (10h)(3600 s/h) = 3.6 × 104 s, so the mass flow rate R is M 5.70 × 106 kg
R=
=
= 158 kg s.
t
3.6 × 104 s 2P4. Average speed, as opposed to average velocity, relates to the total distance, as opposed to the net displacement. The distance D up the hill is, of course, the same as the distance down the hill, and since the speed is constant (during each stage of the motion) we have speed = D/t. Thus, the average speed is Dup +...
View
Full
Document
This document was uploaded on 03/24/2014.
 Spring '14
 Physics, Work

Click to edit the document details