{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}


Similarly lb fb lb ae if is the amount by which

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: to about 2.9 × 108 N/m2, this is approximately the yield strength for the material. 12P48. Since the force is (stress × area) and the displacement is (strain × length), we can write the work integral (Eq. 7- 32) as W = ∫ Fdx = ∫ (stress) A (differential strain)L = AL ∫ (stress) (differential strain) which means the work is (wire area) × (wire length) × (graph area under curve). Since the area of a triangle (see the graph in the problem statement) is 1 2 (base)(height) then we determine the work done to be W = (2.00 × 10−6 m2)(0.800 m)⎛1⎞(1.0 × 10−3)(7.0 × 107 N/m2) = 0.0560 J. ⎝2⎠ 12P49. (a) Let FA and FB be the forces exerted by the wires on the log and let m be the mass of the log. Since the log is in equilibri...
View Full Document

{[ snackBarMessage ]}