Practice_Exam_3[1]

4 x 106 m lrot 2 1 2 i 2i 2 mass of earth 597 x 1024

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Unformatted text preview: ular to the 1 cylinder, through the center of the cylinder I cylinder = ML2 12 ! !! ! A = rA " F I = # mi ri 2 K total = K trans + K rot + K vib K rot = radius of earth = 6.4 x 106 m Lrot 2 1 2 = I$ 2I 2 mass of earth = 5.97 x 1024 kg PHYS 172 – Fall 2010 Exam 3 Machine Graded Portion (70 points total) 1. A playground ride consists of a disk of mass M and radius R mounted on a low ­ friction, vertical axle. The ride is initially at rest. A child of mass m runs in the x direction at spee...
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