problem20_20

University Physics with Modern Physics with Mastering Physics (11th Edition)

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20.20: For a heat engine, ( 29 ( 29 J, 7500 600 . 0 1 ) J 3000 ( 1 / C H = - - - = - - = e Q Q J. 4500 ) J 7500 )( 600 . 0 ( then and H = = = eQ W This does not make use of the given value of ( 29 ( 29 ( 29 K 320 600 . 0 1 K 800 1 engine,
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Unformatted text preview: Carnot a for then used, is If . H C H H =-=-= e T T T T , / and C H C H T T Q Q-= which gives the same result....
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