problem20_18

University Physics with Modern Physics with Mastering Physics (11th Edition)

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20.18: For the smallest amount of electrical energy, use a Carnot cycle. ( 29 J 10 2.09 K) J 10 kg)(334 (5.00 K) 20 ( 4190 kg) (5.00 6 3 K kg J F water freeze C 0 water to Cool in × = × + = + = + = ° mL T mc Q Q Q Carnot cycle: K 293 K 268 J 10 09 . 2 out 6 hot out cold in
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Unformatted text preview: Q T Q T Q = × → = room) the J(into 10 28 . 2 6 out × = Q J 10 09 . 2 J 10 28 . 2 6 6 in out ×-× =-= Q Q W energy) al J(electric 10 95 . 1 5 × = W...
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• NoProfessor
• electrical energy, Heat engine, Carnot cycle, Qin Tcold

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