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TESt afternoon solutions.F06

# TESt afternoon solutions.F06 - TEST 1 Fall 2006 Afternoon...

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Unformatted text preview: TEST 1 Fall 2006 Afternoon OPEN BOOK, OPEN NOTES, OPEN MIND, CLOSE FRIENDS PROBLEM I (20 points) Outcomes 1 & 2 Refrigerant -22 in a piston cylinder arrangement is initially at 50 “C. x=1_ It is then expanded to a pressure of 100 kPa in a process so that at all times P - Av": where A is a constant. a) What are the units and value of A? b) Find the ﬁnal speciﬁc volume and temperature. PROBLEM 2 (30 points) Outcome 2 A rigid 0,1 m": tank contains equal volumes of liquid and vapor of refrigerant 22 at 40 ”C. Additional refrigerant is charged into the tank until the ﬁnal mass is 7'0 kg. If the temperature remains at 40 "C, a) What is the ﬁnal pressure? b) How much mass enters the tank during this process? c) What is the ﬁnal volume of liquid in the tank? PROBLEM 3 (20 points) Outcome 2 A 0.05 m" pressure cooker (closed tank) contains water at 100 "C with the liquid volume being 1,th ot'the vapor volume. The cooker is heated until the pressure reaches 2 MPa. Find the change in volume of the vapor phase. Wafer" ﬂ/ army/{.425 -/ / /:/Z/j}/é/' km #42"? M: 3-3/ r 35%,: s 57. 75,5?” .5 i 7 =14: 2/” :/«W/¢Zfﬂ:‘ ) Z W: 7:71;» &r 72 94M; =9 ﬂz:/5".s¢//%a,«. ﬂ) 4/72/72 w? 2 ”—527; MW/ﬂ 254%, 757* / f/zmu W549” ﬂaw , > y; —y; ‘ ﬂip/ﬂzf—ywﬂ/w" a) W}; 1 252, ¢_¢ _/.f/f/—ﬂ-fFff/Y/ﬂ'3 75:. : mysp/ /@ My,“ Mfﬂﬂsf/J = 857/ ﬂ” mi fﬂz‘:wz%’szi~zéz:ﬁﬁ3éz /é« %erngs[;253¢v/%f/5ﬂw2§fj 1.: 77 “:J' I :3 My ?/V 5; //.//:F / ,_ // 3 7r :ﬂﬂfﬁ #22, V2:- 2 g \$1 W37 y. 76:, #4», £5” 1. j: Ffé'm 3 (4- 7 m; i 1/ : ﬂ7a W ‘V 11/ y: a WWW/7} ...
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