Chemistry 2 notes 5 - " GrAm-i 7‘0 Mo les...

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Unformatted text preview: -/ _ " GrAm-i 7‘0 Mo les CONVEkS/"ou P/tomEMs ZTYFES \‘jf‘nm5 : MOLE: Mqlficuur MASS EXnMPlE: How mnny mole: prg I}: 3/513 Nab”? NaflH = V903 9/55 =- 20. ‘/ m'ole‘ ‘ Ml " > . Lia 5/rhol ' (23 Male: 7"0 3mm: Ibo/(.5 X Ina/(Camr'maw 5 EXAmpIK: l/aw numy among Art I}. 5.00mo/e: 2nd _ 200 3 8’.333/ ' ml, 5.00 rho/3 X 8/.‘383/ : 906.9thms MOI WEIGHT—WEIGHT PROBLEMS Problem #1: (quantity in grams) What weight of oxygen can be iobt‘ained by heating 100 g ofp'otassium chlorate? Solution ' . . K = 39 _ . ~ - Cl”: 35.5 7 ’02 = 32 2. Calculate the total molecular ~ 03‘: 4g 3 02 :96 weight (that is2 the formula . . weight) of each substance under gKCloa ' = 12-2-5 g/mOI consideration. . ~ 2vKClO3 = 245 3. Write the known and required 100 g ' x g weights above, and the calculated 2 KClO3 9 2 KCl + 3 O; A formula weights below. 2.45 _ , g 96 g 4.” Form the proportion. _ 245 x' = 9600 g 5. Cross-multiply, and solve for x. ‘ ’ V x = 39.2 g of oxygen ...
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