Chemistry 2 notes 2 - ,Kfo>j_l< 61 I 3?213 E\Mi‘wqm...

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Unformatted text preview: ,Kfo.>j \ ,,_l < 61'). I 3)}?213 E \Mi‘wqm Ex (€33:C(\__ r K HF" LinnMctxj {rr— c £7255“ E L w 4 / EXERCISE: Calculation of the Molecular formula of a Compound. ALTERNATE METHOD A compound was found to have a molecular weight of 78 g/mol and have a percent composition of 92.3% C and 7.7% H. Calculate the empirical and molecular formulas. Solution: Fill in the table below. Divideb -- , Percent of Molar mass Element smallest ‘ element of element . 7 answer 92.3 12 Divide the percent by the molar mass of the element. Leave the answer to 2—3 decimals for greater accuracy. H Empirical formula CH 9.2% Wt MOLECULAR FORMULA CALCULATION C: “A (MW % H am ? (its? . . . . m " WE“ Misti; 3 “Hal ’9 Convert percents r0 deczmal by dzvzdmg by 100. Q a i. M {0. a: x 7 Subscripts = [(%/100) X MW]/MW of atom C (0.923) X 78 = 71.994/ 12 = 6 H (0.077) X 78 = 6.006/1 = 6 MOLECULAR FORMULA = C6H6 CHE 164: General Chemistry 1 5 , n J [‘7 ...
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