BIOL 2050 Probability example 4 traits

BIOL 2050 Probability example 4 traits - Probability...

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Probability example : 4 traits Question 25, pp 66 in the book The following two genotypes are crossed: AaBbCcddEe x AabbCcDdEe. What will be the proportion of the following genotypes in their offspring? 1) AaBbCcDdEe 2) AabbCcddee 3) aabbccddee 4) AABBCCDDEE
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FIRST Break it down and calculate the proportion of offspring that can result from each trait crossed (you can do punnett squares if you like) Parents : AaBbCcddEe x AabbCcDdEe Locus A: Aa x Aa = ¼ AA, ½ Aa, ¼ aa Locus B: Bb x bb = 1/2Bb, 1/2 bb Locus C: Cc x Cc = ¼ CC, ½ Cc, ¼ cc
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Unformatted text preview: Locus D: Dd x Dd = ½ Dd, ½ dd Locus E: Ee x Ee = ¼ EE, ½ Ee, ¼ ee Answer 1) AaBbCcDdEe: ½ (Aa) x ½ (Bb) x ½ (Cc) x ½ (Dd) x ½ (Ee) = 1/32 2) AabbCcddee = ½ (Aa) x ½ (bb) x ½ (Cc) x ½ (dd) x ¼ (ee) = 1/64 3) aabbccddee = ¼ (aa) x ½ (bb) x ¼ (cc) x ½ (dd) x ¼ (ee) = 1/256 4) AABBCCDD: Will not occur. The AaBbCcddEe parent cannot contribute a D allele. The AabbCcDdEe cannot contribute a B allele. Their offspring cannot be homozygous for BB and DD loci...
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