JH- Exam 3 study. ch 14 Fluorescence

JH- Exam 3 study. ch 14 Fluorescence - Electromagnetic...

Info icon This preview shows pages 1–2. Sign up to view the full content.

Electromagnetic Spectrum What is the frequency of light with a wavelength of a) 1 nm b) 500 nm c) 3 cm? a) 3 × 10 17 s -1 b) 6 × 10 14 s -1 c) 1 × 10 10 s -1 a) ν = c/λ ν = 3 × 10 8 m s -1 / 1 × 10 -9 m ----------------------------- Give the spectral classification of the radiation at each frequency: X-ray = 3 × 10 17 s -1 Visible = 6 × 10 14 s -1 Microwave = 1 × 10 10 s -1 ----------------------------- What is the frequency of orange light (620 nm)? c = 3 × 10 8 m/s ν = c/λ 4.84 × 10 14 s -1 ----------------------------- What is the energy of one photon of orange light (620 nm)? E = hv c = 3 × 10 8 m/s h = 6.626 x 10 -34 Js E = 6.626 × 10 -34 Js × 4.84 × 10 14 s -1 = 3.21 × 10 -19 J Optical Transitions Which of the following statements is not true? 1. The transition dipole moment connects the ground and excited state wave functions. 2. The dipole strength is the square of the transition dipole moment. 3. Wrong: The transition dipole moment is non-zero when the symmetry of the ground and excited state orbitals is the same. 4. The dipole moment operator has odd parity. 5. The dipole moment operator is used to calculate the rate at which molecules in the ground state are transformed to the excited state by the presence of light. ----------------------------- The Einstein coefficient B (the magnitude of the transition probability) determines the intensity of light absorption. Pick the best answer. 1. B is proportional to the dipole strength. 2. B is proportional to the transition dipole moment.
Image of page 1

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern