Homework_1 - ENGG2430D Engineering Mathematics III Problem...

Info icon This preview shows pages 1–2. Sign up to view the full content.

ENGG2430D: Engineering Mathematics III Problem Set 1: Spring 2014 Due: Jan. 22, 2014 TA: [email protected] Reminder : Each student is supposed to turn in a separate solution in their own handwrit- ing. Please put down your own name and student ID in your submitted solution. Notice that all bold math notations are scalars in this problem set. Recap: Permutation : A permutation of a set of distinct objects is an ordered arrangement of these objects. An ordered arrangement of r elements of a set is called an r -permutation. The number of r permutations of a set with n distinct elements is P ( n, r ) = n ! ( n - r )! . Combination : An k -combination of elements of a set is an unordered selection of k ele- ments from the set. A combination is simply a subset of cardinality k . The number of k - combinations of a set with cardinality n with 0 k n is C ( n, k ) = n k = n ! ( n - k )! k ! . Binomial Theorem : Let x , y be variables and let n be a nonnegative integer. Then ( x + y ) n = n X j =0 n j x n - j y j .
Image of page 1

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

Image of page 2
This is the end of the preview. Sign up to access the rest of the document.
  • Fall '14
  • Chairman, telephone numbers

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern