# upload 2 - National University Professor Ben Saida Chapter...

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National University Professor Ben Saida Chapter 9 1-Calculate the Number of moles in these quantities (a) 25.0 g KNO3 Nm =mass/Molar mass Nm= 25.0 g / 101.1g Answer = 0.247 mole KN03 (b) 56 milimole NaOH 56/1000 mmol Answer =0.056 mol NaOH (c) 5.4 x 10^2 g (NH4)2 C2O4 / 124.1g Answer = 4.4 mol (NH4)2 C2O4 (d) 16.8 ml H2SO4 solution (d=1.727g/ml, 80.0% H2SO4 by mass) must covert the solution from ml to g of H2SO4. = 16.8 ml x 1.727g x 0.800g H2SO4 / 98.09g Answer= 0.237 mol H2SO4 3-Calculate the number of grams in these quantities: (a) 2.55mol Fe (OH) 3 = 2.55 mol x 106.9g Answer = 273g Fe (OH) 3 (b) 125 kg CaCO3 = 125 x 1000g = 1.25 x 10^5 g CaCO3 (c) 10.5 mol NH3 10.5mol x 17.03 g = 179 g NH3 (d) 72 milimole HCl /1000 mmol x 36.46g = 2.6g HCl (e) 500.0 ml of liquid Br2 (d=3.119g/ml) 500 ml Br2 x 3.119g / ml = 1.560 x 10 ^3g Br2 (5) Which contains the larger number of molecules. 10.0g H2O or 10.0g H2O2 Water has a lower molar mass than hydrogen peroxide: 10.0 grams of water has a lower molar mass, it has more moles which means more molecules than 10.0g of H2O2.

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(7) (a) Balance the equation for the synthesis of sucrose: 12 CO2 + 11 H2O ----------- C12H22O11 + 12 O2 (Balanced) (b) Set the mole ratio: (a) 12 mol CO2 / 11 mol H2O (b) 11MOL H2O / 1 Mol C12H22O11 (c) 12 mol O2/12mol CO2 (d) 1 mol C12H22O11/ 12 mol CO2 (e) 11 mol H2O /12 mol O2 (f) 12 mol O2/ 1 mol C12H22O11 (9) Given the unbalance equation: CO2 +H2 ----------- CH4 +H2O (a) How many moles of H2O can be produced from 25 moles of CO2? 25 mol CO2 x 2 mol H2O/ 1 mol CO2 Answer = 50 mol H2O (b) How many moles of CH4 will be produced along with 12 moles of H2O? 12 mol H2O x 1mole CH4 / 2 mol of H2O Answer = 6 mol CH4 Chapter 10 1-How many total and how many valence electrons are in each of the following neutral atoms? (a) Element name Valence Electron Total Electron Li 1 3 Mg 2 12 Ca 2 20 F 7 9 11-Electron configuration for the diagrams given (a) O 1s2 2s2 2p4 (b) Ca 1s2 2s2 2p6 3s2 3p6 4s2 (c) Ar 1s2 2s2 2p6 3s2 3p6 (d) Br 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p5 (e) Fe 1s2 2s2 2p6 3s2 3p6 4s2 3d6 39- Classification of elements (a) K is a metal (b) Pu is a metal (c) S is a nonmetal (d) Sb is a metalloid 49- Which ones will have the same number of valence electron? Answer: Na +, F- & Ne have the same valence electron: 8 valence electron 64-What is the family name for:
(a) Group 1 A =Alkali metals (b) Group 2A = Alkali Earth metals (c) Group 7A = Halogens Chapter 11 5- Indicate which element is more positive and which one is more negative (a) H is more + O is more - (b) Rb is more + Cl is more (c) H is more + N is more - (d) Pb is more + S is more – (e) P is more + F is more – (f) H is more + C is more – 7- Classify the bond (a) Covalent

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• Spring '14
• Mole, mol, 0.125M H2SO4, Valence Electron Total Electron

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