Test 2 b solutions - Name(Please PRINT 5 OIU ‘4 G“...

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Unformatted text preview: Name (Please PRINT) 5 OIU ‘4 G“ ' October 30, 2012 Mechanical Engineering Technology , MET41411: Machine Design I "'——— TEST 2 100 Notes: Closed book. No other material is allowed except a calculator. Time allowed 60 minutes. Points for each question are shown in [xx]. Must show necessary formulae, setup and calculations to get full credit. Always write the units as appropriate. Draw a box around each answer. 1. A 4”x4” wooden column (Sy=6,000psi, Su=10,000 psi, E=55,000 psi) 96 inches tall is axially 25 loaded. One end is in the ground (fixed) and the other end is pinned. (a) Determine whether [ ] Euler or Johnson formula should be used. (b) Calculate the critical buckling load. Show all work. . 3 , ,. .L/ jEEi/I —a I: 97—47: = 2/33 (hf ', fl: 4/)(‘1’N3/h (I, - . /c'—‘ 0-71‘Z='7 (96226792 6530‘». MD Teer Fall 2012 Page 1 You may work on the back side, if necessary 9 Name (Please PRINT) October 30, 2012 2. A high pressure cylinder is used for storing compressed air in trucks. The cylinder is 250 mm in internal diameter and 1.5 m long with hemispherical ends. Internal pressure is 125 MPa, and safety factor of 2.0 must be used. The material of the cylinder is stainless steel (ferritic: E=200 GPa, Sy=345 MPa, Su=552 MPa, ) Using DET or MSST calculate the necessary wall thickness. Write your assumptions if any. You may neglect axial stress if necessary for simpler calculations. [3 or +V a at TTHN 0711‘KdJW: 61766 7 “Sum 67": or: 7 f3: 6r=0. [25] ’6' E: +UO. 7/? MD Test2 Fall 2012 Page 2 You may work on the back side, if necessary 9 Name (Please PRINT) October 30, 2012 3. For the part sho - [30] from 600 lbs to -300 I .. I. a . 4m ((01; ‘ Mm ’ t l . I \ N Iraq. ( If I s“ Mm“ , = 2 '7‘? [.25 Mrw =- (it) 6' -:Lw:il —_6255. '22; p5.“ .= b3m(q):-l/{2uz>14 Duh — - 7 may w UJ/flMZL 1:77; 6‘, €mw+€rm4_ 72,515‘9,3‘H+(—525&1?29 I: (DJ/9%?” “(7 “Maw : '2’ " 2 5m = *3/2711 P5)" gm («am a . - -7 3 /~— '5(§Uq ztsjmtwfk 40,027 ksr fig? 9( 5 Q _ ,9 3’2 : law/(9,, Q 13”; Se, Wake " (92314105475908? (umwwj 3 ,1; \ l? = e - “035' = 2 7’25” = #39 (sags?) \“‘“‘“—"/ r ~ 2 a 9232“ LM0W%M WW gham ) \c/ / //“/y —~//L 61A ‘ +W -' ‘0" C) m #3» 18390 257 ‘ __ g?— 27.29f RI: .84755 vw‘ca/v 78%» 57 k2 :50 m— m 34 QM” ———— Q ‘ W flaw“ "Q / _ Eg—Eu /- (/.439(80'0§f/ ($111) 2 93-63/8 > (To; =3./29 ks,’ Kai (Avg? SJ ’Qf/‘m KC” 9e 5 i . mm A)» 6m 1- (9.1 S“ ~/j— Wf 27.2; _ 274505 4;», 4er /2rS”/é+ 3,/24(/;93g {-80.0533 -1) - )7; (#935) 5 MD Test2 Fall 2012 Page 3 You may work on the back side, if necessary 9 Name (Please PRINT) Ami j - Z October 30,2012 [20] 4. A 1000 lb rescue boat was being dropped from the side of a ship at the velocity of 200 ft/min when suddenly the 2 cables jammed on the pulleys and stopped. At that moment the boat was hanging down 100 ft. Two cables are made of material with E=15E6 psi and each has a diameter of 0.85 inch. Calculate the max elongation, and max stress in the cable. o "L ’1/ P £5! ~ lgx/O‘)(/'/3L/q = I63/86w75” «Sfawcmt. m g= z - «may ' M4 '\ . _ 20mm; 53’3" 7 may a flab/“7% ‘ T: 90 4“ :32'7 3612:. 386‘17‘ 5 — 3K ‘ woo =704908 AW“: “0705 mg sM‘c‘ K ‘ "0’8ng X/C’FL MD Test2 Fall 2012 Page 4 You may work on the back side, if necessary -) ...
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