Mendelian Genetics.1 pp.Handout.2013

# Step 2 re calculate the expected genotypic

This preview shows page 1. Sign up to view the full content.

This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: ___ •  q(y) = freq (yy) + ½ freq (Yy) = _____ + _____ = _____ Q2: Is the population still in Hardy-Weinberg equilibrium? Q2. Is the population still in Hardy-Weinberg equilibrium? Step 2: Re-calculate the EXPECTED GENOTYPIC frequencies •  p(Y) = freq (YY) + ½ freq (Yy) = 0.36 + 0.14 = 0.50 •  q(y) = freq (yy) + ½ freq (Yy) = 0.36 + 0.14 = 0.50 p2 = 0.52 = _____ 2pq = 2(0.5 x 0.5) = _____ q2 = 0.22 = _____ " Genotype Observed Genotype Frequency Expected Genotype Frequency YY 0.36 _____ Yy 0.28 _____ yy 0.36 _____ Now I can rest A. Nope...it's NOT in HardyWeinberg equilibrium. Another VERY SIMPLE Hardy-Weinberg problem... 4. A moth has three alleles at a locus that controls antenna color: X1, X2 and X3. X1 is dominant to X2 and X3; X1 produces red antennae. X2 is co-dominant to X3; X2X2 produces yellow antennae, X3X3 produces white antennae, and X2X3 produces light yellow antennae. The phenotypic frequencies in a population are as follows: 0.04 WHITE " 0.16 LIGHT Y ELLOW "0.16 Y ELLOW " 0.64 RED ⇒ Assuming that this population is in Hardy-Weinberg equilibrium, what is the frequency of the X3 allele in this population? "a) 0.04 "b) 0.20 "c) 0.16 "d) 0.32 "e) 0.64...
View Full Document

## This document was uploaded on 01/06/2014.

Ask a homework question - tutors are online