Expt3 Bradford Assay- Sample Journal Article Report F09

511 094 088 323 328 400 absorbance 419 359 263 147

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Unformatted text preview: rall Dilution Factor* 5/7 20/49 40/147 40/294 40/588 40/1176 Absorbance .511 .094 .088 .323 .328 .400 Absorbance .419 .359 .263 .147 .069 .030 Absorbance Absorbance vs. Concentration y = 0.0004385x + 0.0125865 R2 = 0.9910977 0.4 0.35 0.3 0.25 0.2 0.15 0.1 0.05 0 Series1 Linear (Series1) 0 200 400 600 800 1000 Concentration (μg/mL) The first step in analyzing the results was to determine the standard curve for standard solutions of bovine serum albumin by plotting a graph of absorbance vs. concentration. The data point with the highest concentration of protein was disregarded because it was an outlier that did not fit the rest of the data. The inclusion of that point suggested an almost logarithmic curve. The linear graph without that data point, then, had a R2 value of .9911, which was relatively good because it indicated that most of the points fell relatively close to the best fit line drawn. By using the standard curve, the unknown concentrations were found by finding the concentration corresponding to the absorbance measured, and then multiplying by the dilution factor to find the actual concentration of the unknown. The four results averaged out to be about 8038 μg/mL, or 8.038 mg/mL, with a standard deviation of 8038 μg/mL ± 1080 μg/mL. Calculations: Using the equation of the standard curve and graphical analysis: A1: Y = 0.0004385x + 0.0125865 .323 = 0.0004385x + 0.0125865 x = 707.8 μg/mL Since it is a 10x dilution,...
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