problem20_41

# University Physics with Modern Physics with Mastering Physics (11th Edition)

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20.41: a) K 15 . 290 K, 15 . 268 J, 00 . 1 H C = = = T T W For the heat pump 0 Q and 0 H C < Q H C H C H C with this combining ; T T Q Q Q Q W - = + = gives J 2 . 13 290.15) 268.15 ( 1 J 00 . 1 1 H C H = - = - = T T W Q b) Electrical energy is converted directly into heat, so an electrical energy input of 13.2 J would be required. c) From part (a), C H H C H as decrease 1 T Q T T W Q - = decreases. The heat pump is less efficient as the temperature difference through which the
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Unformatted text preview: heat has to be “pumped” increases. In an engine, heat flows from C H to T T and work is extracted. The engine is more efficient the larger the temperature difference through which the heat flows....
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