MSE160 2014 Quiz 1 (Ver.1) Solutions

bz 2 bz 2 ie 5 2 2 n1 n2 1 1 1 ie 5 218x10

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Unformatted text preview: point, Boron is a one electron ion (B4+) which means we can use the above equation. The removal of an electron from a one electron atom/ion corresponds to raising the electron to the Bohr orbit of n = ∞. Therefore, the 5th ionization energy (IE5) can be described as the difference between energy levels of the n=1 and n=∞ Bohr orbits. -bZ 2 -bZ 2 IE 5 = 2 - 2 n1 n2 ! 1 1$ 1 IE 5 =- ( 2.18x10 -18 J ) ( 52 )# 2 - 2 & but 2 → 0, so "∞ 1 % ∞ ! 1$ IE 5 =- ( 2.18x10 -18 J ) ( 52 )#- 2 & "1% IE 5 = ( 5.45x10 -17 J/electron ) ( 6.022x10 23 electrons/mol) IE 5 =32800 kJ/mol 4. Give the complete set of quantum numbers for all the electrons that could...
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