In case of single pipe we have total poisson arrival

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Unformatted text preview: ider m statistically identical and independent Poisson packet streams each with an arrival rate of =m packets per sec, transmitted over a communication link with exponentially distributed service time with mean service rate . In case of single “pipe", we have total Poisson arrival as m=m =  due to one of properties of Poisson process mentioned earlier. Using M/M/1 model, we get the avg. delay to be 1 Ta =  ,  : If, in, the link is divided into m separate pipes (partitioned), then the service rate of each pipe is =m, i.e., 1=m-th of the rate of the original pipe. In this case, the avg. delay (again using M/M/1 on one partition): 1 Tb = =m , =m =  m  : , Thus, splitting the line into m pipes increases the avg delay by m times! This is an interesting phenomenon about statistical multiplexing; as a rule of thumb, it is better to have a fatter link than partition the link into lower speeds since it results in more delay on average. What about the effect on average number of pac...
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This document was uploaded on 03/19/2014 for the course CS 6030 at Western Michigan.

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