5 feldman s notes 3 2 check 5 2 2t 2t 2 5 2 3

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Unformatted text preview: x5 5 = t, x1 = − 2 − 2t 3 = −2 =2 =1 Example II.5 (Feldman s notes) 3 2 – Check − 5 2 − 2t + 2t − 2− 5 2 3 − 2t + 4t + 4 − 2 + 6 × 2 + 1 = 2 3− 5 2 − 2t + 6t − − 5 2 3 − 2t + 2t + 3 − 2 + 5 × 2 + 1 = 4 3 2 +2×2+1=1 +4×2+5=4 (− 5 − 2 3 2 + 2 × 2 + 1) + (−2 + 2) t = 1 (1’) −4× 3 2 + 6 × 2 + 1) + (−2 × 2 + 4)t = 2 (2’) 5 2 − 3 2 + 4 × 2 + 5) + (−3 × 2 + 6)t = 4 (3’) (− 5 − 3 × 2 3 2 + 5 × 2 + 1) + (4’) (−2 × 5 2 (−3 × (−2 + 2) t = 4 (1) + (0)t = 1 (1’) (2) + (0)t = 2 (2’) (4) + (0)t = 4 (3’) (4) + (0)t = 4 (4’)...
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This note was uploaded on 04/01/2014 for the course MATH 307 taught by Professor Richardfroese during the Fall '08 term at The University of British Columbia.

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