Practice Final Ans

Practice Final Ans - Abbreviated Answers to Example Exam-II...

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Abbreviated Answers to Example Exam-II Question #1 (a) synthase or lyase (b) One molecule of carbonic anhydrase coverts (turnsover) 1.5 x 10 5 molecules of CO 2 to product every second under saturation conditions. (c) (i) Vmax = 5.88 mmol/min = 9.8 x 10 -5 mol/sec, E = 6.5 x 10 -10 mol = 19.5 μ g. (ii) Km = 5.88 mmol/min x 1.5 min/L = 8.8 mM (iii) Km represents the [S] required to maintain 50% filling of the enzyme active sites during the course of the enzyme assay and thus yield a reaction rate, v = 1/2 Vmax. (d) (i) No (ii) If the inhibitor was binding non-covalently in the active site one should be able to to overcome the inhibition by using a high concentration of substrate. The graph indicates increasing the concentration of [S] does not overcome the effect of the inhibitor, that is, the lower (+I) curve does not approach the upper (-I) curve as the [S] is increased. This is not consistent with competetive inhibition. Question # 2 (a) G’ = + 5.7 kJ/mol (b) Qcell’ cannot equal or exceed 3.78 x 10 4 (c) Step #1: Carboxylate-O - of N-terminal glycine = nucleophile;
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Practice Final Ans - Abbreviated Answers to Example Exam-II...

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