Practice Final Ans

Ii for both components 11 using 4hatp or 1331 using

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Unformatted text preview: . (ii) For both components 1:1 (using 4H+/ATP) or 1:33:1 (using 3H+/ATP) for part marks. (c) (i) Yes. Work to synthesize 4 mol of ATP = 126 kJ. Energy from oxidation of 1 mol of Vitamin C = 146.2 kJ. Since 146.2 > 126 kJ there is enough energy to do the work required with enough left over to give the overall process a ∆Go’ < 0. (ii) ∆G’= 2476 ln (10-7/10-6) + (+1)(96, 480)(-0.18) = -23.0 kJ/mol H+ transported. 23.0 kJ of energy produced/mol H+ transported x 3 mol H+ = 69 kJ energy produced Question #4 ( a) O CH3CH2C O - NAD+ + C + CoASH O Dehydrogenase O CH3CH2C SCoA + NADH + CO2 O HO Synthetase P O- O- HSCoA O O CH3CH2C OP O O - - ADP O CH3CH2C O O (b)(i) ATP + - O CH3CH2C O P O O + H2 O CH3CH2C O - CH3CH2C O O OP O O - - - + HO P O (ii) O O O - CH3CH2C - O + OPO O - O - - + H+ Question #5 (a) (CH2)14 C O - + (AMP + PPi is OK too, can't tell without more information) O 1 O CH3 ADP + Pi ATP CH3 HSCoA (CH2)14 C S CoA 1/2 O2 2 H 2O O H CH3 (CH2)12 Reactions 2,3,4,5 repeated until the entire fatty acid has been converted to Acetyl CoA CCCS CoA H H 2O 3 H CH3 (CH2)12 O C CH2 CS OH CoA NAD+ 4 NADH O CH3 (CH2)12 C S O 5 CoA CH3 CS (b) Pantothenic acid (c) Reaction Reaction similar to which Glycolysis or TCA cycle reaction? C CH2 CS HSCoA O CH3 (CH2)12 O CoA Systematic enzyme name (1 word) Names...
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This test prep was uploaded on 04/01/2014 for the course BIOL 201 taught by Professor Chowrira during the Winter '13 term at UBC.

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