Practice Final Ans

# Ii for both components 11 using 4hatp or 1331 using

This preview shows page 1. Sign up to view the full content.

This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: . (ii) For both components 1:1 (using 4H+/ATP) or 1:33:1 (using 3H+/ATP) for part marks. (c) (i) Yes. Work to synthesize 4 mol of ATP = 126 kJ. Energy from oxidation of 1 mol of Vitamin C = 146.2 kJ. Since 146.2 > 126 kJ there is enough energy to do the work required with enough left over to give the overall process a ∆Go’ < 0. (ii) ∆G’= 2476 ln (10-7/10-6) + (+1)(96, 480)(-0.18) = -23.0 kJ/mol H+ transported. 23.0 kJ of energy produced/mol H+ transported x 3 mol H+ = 69 kJ energy produced Question #4 ( a) O CH3CH2C O - NAD+ + C + CoASH O Dehydrogenase O CH3CH2C SCoA + NADH + CO2 O HO Synthetase P O- O- HSCoA O O CH3CH2C OP O O - - ADP O CH3CH2C O O (b)(i) ATP + - O CH3CH2C O P O O + H2 O CH3CH2C O - CH3CH2C O O OP O O - - - + HO P O (ii) O O O - CH3CH2C - O + OPO O - O - - + H+ Question #5 (a) (CH2)14 C O - + (AMP + PPi is OK too, can't tell without more information) O 1 O CH3 ADP + Pi ATP CH3 HSCoA (CH2)14 C S CoA 1/2 O2 2 H 2O O H CH3 (CH2)12 Reactions 2,3,4,5 repeated until the entire fatty acid has been converted to Acetyl CoA CCCS CoA H H 2O 3 H CH3 (CH2)12 O C CH2 CS OH CoA NAD+ 4 NADH O CH3 (CH2)12 C S O 5 CoA CH3 CS (b) Pantothenic acid (c) Reaction Reaction similar to which Glycolysis or TCA cycle reaction? C CH2 CS HSCoA O CH3 (CH2)12 O CoA Systematic enzyme name (1 word) Names...
View Full Document

## This test prep was uploaded on 04/01/2014 for the course BIOL 201 taught by Professor Chowrira during the Winter '13 term at UBC.

Ask a homework question - tutors are online