# A reduce the laser wavelength b reduce the slit width

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Unformatted text preview: is a corresponding point in the bottom half that cancels it. θ P L The second minimum is at an angle such that the light from the top and a point at a/4 destructively interfere: a λ δ = sin θ min,2 = 4 2 Location of nth-minimum: ⇒ sin θ min,2 = sin θ min,n 2λ a nλ = a ACT 2 a 1 cm = W 2m Which of the following would broaden the diffraction peak? a. reduce the laser wavelength b. reduce the slit width c. move the screen further away d. a. and b. e. b. and c. Lecture 4, p 23 ACT 2 - Solution a 1 cm = W 2m Which of the following would broaden the diffraction peak? a. reduce the laser wavelength b. reduce the slit width c. move the screen further away d. a. and b. e. b. and c. Lecture 4, p 24 Single-slit Diffraction — Summary The intensity of a single slit has the following form: ⎛ྎ sin( β / 2) ⎞ྏ I1 = I0 ⎜ྎ ⎟ྏ ⎝ྎ β / 2 ⎠ྏ 2 Derivation is in the supplement. δa = a sinθ ≈ aθ θ 1I01 a Observer (far away) diff ( x) 0.5 I 0 β θ 00 -4π P 10 -2π 12.56 λ/a - 00 x 0 2π λ/a 10 4π L &gt;...
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