Solubility Homework Set

# Kspforcdco3is52x1012

This preview shows page 1. Sign up to view the full content.

This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: CN. Cadmium ion forms the complex ion, Cd(CN)42‐ for which Kf is 6.0 x 1018. 2 Dr. Fus CHEM 123 35. Calculate the molar solubility of CdCO3 in 1.5 M NH3. Note that Cd2+ forms the Cd(NH3)42+ complex ion for which Kf is 1.3 x 107. Ksp for CdCO3 is 5.2 x 10‐12. 36. What is the concentration of free cobalt ion in a solution that is 4.75 x 10‐2 M Co2+ and 5.0 M NH3? Kf Co(NH3)62+ = 8.3 x 104 37. Calculate the molar solubility of AgCl in 12 M NH3. Kf Ag(NH3)2 = 1.7 x 107 Ksp AgCl = 1.8 x 10‐10 38. Calculate the concentration of free aluminum ion, [Al3+], in 1.0 L of solution that contains 0.040 mol Al(NO3)3 and 2.00 mol NaF. Kf for AlF63‐ is 7.1 x 1019. 39. The Cd2+ ion forms the complex ion CdCl42‐ for which Kf = 6.3 x 102. Determine the equilibrium constant for the solubility of CdCO3 in contact with a solution that contains Cl‐ ion. Ksp for CdCO3 is 5.2 x 10‐12. 40. Use information from problem 39 to calculate the molar solubility of CdCO3 in 3.0 M NaCl. 41. The Ag+ ion forms the com...
View Full Document

## This homework help was uploaded on 03/28/2014 for the course CHEM 123 taught by Professor Larosa during the Spring '06 term at Ohio State.

Ask a homework question - tutors are online