Unformatted text preview: CN. Cadmium ion forms the complex ion, Cd(CN)42‐ for which Kf is 6.0 x 1018. 2 Dr. Fus CHEM 123 35. Calculate the molar solubility of CdCO3 in 1.5 M NH3. Note that Cd2+ forms the Cd(NH3)42+ complex ion for which Kf is 1.3 x 107. Ksp for CdCO3 is 5.2 x 10‐12. 36. What is the concentration of free cobalt ion in a solution that is 4.75 x 10‐2 M Co2+ and 5.0 M NH3? Kf Co(NH3)62+ = 8.3 x 104 37. Calculate the molar solubility of AgCl in 12 M NH3. Kf Ag(NH3)2 = 1.7 x 107 Ksp AgCl = 1.8 x 10‐10 38. Calculate the concentration of free aluminum ion, [Al3+], in 1.0 L of solution that contains 0.040 mol Al(NO3)3 and 2.00 mol NaF. Kf for AlF63‐ is 7.1 x 1019. 39. The Cd2+ ion forms the complex ion CdCl42‐ for which Kf = 6.3 x 102. Determine the equilibrium constant for the solubility of CdCO3 in contact with a solution that contains Cl‐ ion. Ksp for CdCO3 is 5.2 x 10‐12. 40. Use information from problem 39 to calculate the molar solubility of CdCO3 in 3.0 M NaCl. 41. The Ag+ ion forms the com...
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This homework help was uploaded on 03/28/2014 for the course CHEM 123 taught by Professor Larosa during the Spring '06 term at Ohio State.
- Spring '06