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thermodynamics recitation 509&514

# 6kj mol 83145 37 mm 38mm j 310k ln 1mm

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Unformatted text preview: ȹ Ⱥ ΔG = −12.6kJ / mol + 8.3145 ȹ [13mM ] × [4mM ] ȹ J × 310K × lnȹ ȹ [25mM ] × [0.013mM ] ȹ = 0.48kJ / mol ȹ mol • K ȹ Ⱥ c) ( 1 pt) Aber vigorous exercise, the concentra3on of the metabolites in muscle 3ssue is: [ATP] = 3.8 mM [ADP] = 0.113 mM [Crea3ne] = 37 mM [Phosphocrea3ne] = 1 mM Calculate ΔG for the reac3on shown above using these metabolite concentra3ons at 37 ⁰C. ȹ ȹ [Creatine] × [ ATP] ΔG = ΔG o '+ RT lnȹ ȹ [Phosphocreatine]× [ ADP] ȹ ȹ ȹ Ⱥ ΔG = −12.6kJ / mol + 8.3145 ȹ [37 mM ] × [3.8mM ] ȹ J × 310K × lnȹ ȹ [1mM ] × [0.113mM ] ȹ = 5.78kJ / mol ȹ mol • K ȹ Ⱥ 4 . a) Write...
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