186 copyrightc 2005 by ali ghalambor boyun guo 93

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Unformatted text preview: re known. Remaining is to check the reductions in burst and collapse resistances caused by biaxial loading. Fig.33 shows tension loading versus depth after cementing, is used to evaluated the effect of biaxial loading. 186 Copyright(c) 2005 by Ali Ghalambor & Boyun Guo 93 Fig.33 Biaxial Design 187 Point Loading Calculation ⎡ ⎤ 6 KJ Fb = 218 Dp φ As ⎢ Tanh ( 6 KJ ) ⎥ ⎣ ⎦ Where: Fb = Bending Force(Additional Tension Load) (lbs.) Dp = Diameter of Pipe (inches) φ (Eq.5) = Dogleg Angle(degrees) K= Tension Load At Point (lbs) EI E = Modulus of Elasticity π I = Moment of Inertia = ( OD 64 (Eq.6) 4 p − ID Idp = Inside Diameter of Pipe (inches) J = Joint Length (30 ft. or 40 ft) Tanh = Hyperbolic Tangent of (Value: 6KJ) Tanh(X) = e x − e − x e x + e −x 4 p ) (Eq.7) (Eq.8) Copyright(c) 2005 by Ali Ghalambor & Boyun Guo 188 94 Intermediate Casing With A Drilling Liner, and The Liner Design Burst Design The simultaneous equations to be used are: X+Y=SDL (Eq.9) SP+X·GML+Y ·Gg=Inj.P. (Eq.10) Where: IPL=(FGL+SF)(0.052)(SDL) X=Length of Heavi...
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