Well-Control-Plan

Calculate the reduction in pressure by puling 10

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Unformatted text preview: he inability apply conventional kill procedures. Copyright(c) 2005 by Ali Ghalambor & Boyun Guo 60 Well Control Problems A. Calculate the reduction in pressure by puling 10 stands of 4 ½”, 16.6 #/ft., drill pipe. Extra hole tool joints having an outside diameter of 6 ¼” O.D. and 3 ¼” I.D., w/o filling the annulus. Displace is 0.00663 bbls/ft. or 151feet per barrel. The hole diameter is 8 ½”, and annulus volume is 20 feet per barrel of 0.05 bbl. Per foot. The capacity of the drill pipe is 0.142 bbl/ft. the mud weight is 16.8 lb/gal and well depth is 10,000 feet. A stand length is 93 ft. 121 Solution: 10×93= 930 ft 930×0.00663=6.6166 bbls displacement 6.6166/0.0642=96.04 ft 96.04×872psi/ft=83.74 psi 83.74 pulling 10 stands without filling the casing annulus 122 Copyright(c) 2005 by Ali Ghalambor & Boyun Guo 61 B. Calculate the reduction in pressure by pulling a stand of collars w/o filling up the hole. The collars are 7” O.D. by 2.5” I.D. in an 8 ½” hole. The mud weig...
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This document was uploaded on 03/28/2014.

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