You will want to keep cl to filter the output but rl

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Vout which goes to the negative input of R2 the error amplifier. f is the division ratio of the voltage divider, i.e., f = and A is R1 + R2 the gain of the error amplifier/pass element combination. The output voltage of the pass element is Vout = A Vref − fVout . Solving for Vout this expression can be rewritten as ( Vout = AVref 1 + fA → Vout → Vref f Vref f ) which, in the limit as A → ∞ , becomes (1) When designing a regulated power supply, we typically use an integrated circuit regulator. The popular 78xx series three- terminal voltage regulator internally uses a circuit which is similar to the one in Figure 3 and similar to the circuit you will analyze in this lab. These regulators are easy to use and often provide other capabilities such as current limiting, short- circuit protection and temperature compensation. However,...
View Full Document

This document was uploaded on 04/02/2014.

Ask a homework question - tutors are online