Unformatted text preview: andard isentropic relations for M1=3.6,
( ) ( ) Therefore, Also from appendix B, we have This value of P02 is much lower than that computed from the ratio , and this value is incorrect. PROBLEM 1d
The strongest weak shock solution is found by locating the maximum deflection angle for the M=2.8
curve on the
chart,
. The corresponding maximum wave angle is determined to be The normal component of the Mach number M1 is then
( ) ( ) From appendix B for this Mach number we find Hence
PROBLEM 1e
From the chart, for and M=3.0 , we find The normal component () From appendix B, for , ( ( ) ( ) ) Also The downstream flow behind the oblique shock is supersonic, and hence a bow shock is formed in front
of the pitot probe. We hence make use of the RayleighPitot formula in Appendix B.
For M=1.4201 Hence the total pressure sensed by the pitot tube is PROBLEM 2a
From the chart, with and The normal component () From appendix B, for we have , ( ( ) ( ) ) Note: The computation described below is not required for part (a).
The pressure coefficient for the wedge can be calculated using (
( ) ) ( ) PR...
View
Full Document
 Spring '09
 COLLICOTT
 Fluid Dynamics, Mach number, Shock wave, Oblique shock, Rayleigh Pitot

Click to edit the document details