PS5_solution

6 we have from standard isentropic relations for

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Unformatted text preview: andard isentropic relations for M1=3.6, ( ) ( ) Therefore, Also from appendix B, we have This value of P02 is much lower than that computed from the ratio , and this value is incorrect. PROBLEM 1d The strongest weak shock solution is found by locating the maximum deflection angle for the M=2.8 curve on the chart, . The corresponding maximum wave angle is determined to be The normal component of the Mach number M1 is then ( ) ( ) From appendix B for this Mach number we find Hence PROBLEM 1e From the chart, for and M=3.0 , we find The normal component () From appendix B, for , ( ( ) ( ) ) Also The downstream flow behind the oblique shock is supersonic, and hence a bow shock is formed in front of the pitot probe. We hence make use of the Rayleigh-Pitot formula in Appendix B. For M=1.4201 Hence the total pressure sensed by the pitot tube is PROBLEM 2a From the chart, with and The normal component () From appendix B, for we have , ( ( ) ( ) ) Note: The computation described below is not required for part (a). The pressure coefficient for the wedge can be calculated using ( ( ) ) ( ) PR...
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