problem19_65

University Physics with Modern Physics with Mastering Physics (11th Edition)

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19.65: a) J, 187 K) 150 K)( mol J 5 mol)(8.314 150 . 0 ( - = - = = = T nR V p W J. 467 J, 654 K) 150 K)( mol J mol)(29.07 150 . 0 ( - = - = - = - = = W Q U T nC Q p b) From Eq. (19.24), using the expression for the temperature found in Problem 19.64, J, 113 ) 2 1 ( K)(1 K)(150 mol J 5 mol)(8.314 150 . 0 ( 40 . 0 1 40 . 0 = - = W 0 = Q for an adiabatic process, and . 0 so , 0 c)
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Unformatted text preview: = =-=-=-= ∆ W dV W W Q U Using the temperature change as found in Problem 19.64 and part (b), J. 580 and J, 580 K) 113.7-K K)(300 mol J mol)(20.76 150 . ( = =-= ∆ = ⋅ = ∆ = Q W Q U T nC Q V...
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  • mol, Adiabatic process

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