1383069877_750__HW4solution

5 10 40 1 40 4 10 by the above figure

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Unformatted text preview: )+ ( )= ( 0) τ = 8 = 8 × 0.5 × 10 ∴ ( ) = 40 ∴ (1) = 40 = 4 × 10 By the above figure τ= ( )= = 0.5 × 10 () (1) = Problem 4: × 20 = 10 ( = 40 (t) = Also by KVL (t) = 2 () ∴ ∴ Since ∴ ∙ 10 = 10 + −( + ) ∙ 2 = −2 () (t) = =− 2 ( )= ( ) = −4 ( ) (0) (0 ) = (0 ) = 25 ∴ ( ) = 25 () = 0.5 × (−4) × 25 ( )= ) = −50 Problem 5: By inspection, (0 ) = (0 ) = −6 For > 0, the Thevenin equivalent is determined by () () ∴ =− ∴ ∴ ( )= ( )= ∙ (0) = −6 6 = 0.5 ∙ 6+3 . (−6 = (6 + 3)||72 = 8 = −6 )∙ 2 = 32 3...
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