problem19_61

University Physics with Modern Physics with Mastering Physics (11th Edition)

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19.61: a) For as isothermal process for an ideal gas, J. 300 so 0, and 0 = = = = W Q U T b) For an adiabatic process, Q = 0, and J. 300 - = - = W U c) For isobaric, . d or , d nR W T T nR pdV W = = = Then, T nC Q d p = and substituting for d T gives . d use , find To
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Unformatted text preview: J. 750 Thus, J). 300 ( or , 2 5 2 5 T nC U U Q R Q C nC Q V R W R W p nR W p = ∆ ∆ = = = = = Substituting for J. 450 ) ( , and d 2 3 2 3 = = = ∆ W nR W R n U C T V...
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  • Adiabatic process, nCV dT, nCp dT

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