problem19_59

University Physics with Modern Physics with Mastering Physics (11th Edition)

This preview shows page 1. Sign up to view the full content.

19.59: a) From constant cross-section area, the volume is proportional to the length, and Eq. (19.24) becomes ( 29 γ p p L L / 1 2 1 1 2 = and the distance the piston has moved is ( 29 Pa 10 5.21 Pa 10 01 . 1 1 m 250 . 0 1 400 . 1 / 1 5 5 / 1 2 1 1 2 1 × × - = - = - γ p p L L L m. 0.173 = b) Raising both sides of Eq. (19.22) to the power γ and both sides of Eq. (19.24) to the power 1 - γ , dividing to eliminate the terms ) 1 ( 2 ) 1 ( 1 and - - γ γ γ γ V V and solving for the ratio of the temperatures, ( 29 ( 29 ( 29 C. 206 K 480 Pa 10 1.01 Pa 10 21 . 5 K 15 . 300 400 . 1 1 1 5 5 / 1 1 1 2 1 2 ° = =
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern