problem19_59

University Physics with Modern Physics with Mastering Physics (11th Edition)

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19.59: a) From constant cross-section area, the volume is proportional to the length, and Eq. (19.24) becomes ( 29 γ p p L L / 1 2 1 1 2 = and the distance the piston has moved is ( 29 Pa 10 5.21 Pa 10 01 . 1 1 m 250 . 0 1 400 . 1 / 1 5 5 / 1 2 1 1 2 1 × × - = - = - γ p p L L L m. 0.173 = b) Raising both sides of Eq. (19.22) to the power γ and both sides of Eq. (19.24) to the power 1 - γ , dividing to eliminate the terms ) 1 ( 2 ) 1 ( 1 and - - γ γ γ γ V V and solving for the ratio of the temperatures, ( 29 ( 29 ( 29 C. 206 K 480 Pa 10 1.01 Pa 10 21 . 5 K 15 . 300 400 . 1 1 1 5 5 / 1 1 1 2 1 2 ° = =
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This document was uploaded on 02/06/2008.

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