3 x spring 2006 quiz 1 6641 spring 2005 solution a e

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: = − ln x + φ + ln x 4 π ε0 −L 0 L a λ − ln + π + ln = = 4 π ε0 L a L x =a λdx 4π ε0 (x) L a λ 4π ε0 (π + 2 ln L ) a B Question: Find the electric field (magnitude and direction) at (x = 0, y = 0, z = 0). 3 x Spring 2006 Quiz 1 6.641, Spring 2005 Solution: −a E (x = 0, y = 0, z = 0) = x =− L λix dx + 4π ε0 x2 π φ=0 π λ(−ir )adφ + 4 π ε 0 a2 L x=a λ(−ix )dx 4π ε0 x2 1 1L λ − cos φix − sin φiy − dφ + ix + ix 4 π ε0 x −L a xa φ=0 π π 1� 1� λ 1 1� 1� − � + � ix + − sin φ ix + cos φ iy + � − � ix = 4 π ε0 − − a L� a 0 0 � � a �L −a...
View Full Document

Ask a homework question - tutors are online