641 spring 2005 q2 1 6 0 mz 2 d 2 vz 2 q2 dz 1

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Unformatted text preview: Quiz 1 ⇒ 2 vz 2 d dz 6.641, Spring 2005 =− q2 ⇒ 1 6 π ε 0 mz 2 d 2 vz 2 = − q2 dz 1 6 π ε 0 mz 2 q2 +C 8 π ε 0 mz Use I.C. vz (z = d) = 0 2 ⇒ vz = + 2 q ⇒ C = − 8πε0 md 2 vz = q2 8 π ε0 m 11 − z d q2 8π ε0 m ⇒ vz (z ) = − 1 z − 1 d since particle is moving towards the conducting ground plane v = vz iz (vz has minus sign) B Question: How long do es it take the charge to reach the z = 0 ground plane? Hint: dz 1 z − z d−z 3 1 d = − z d(d − z ) + d 2 tan−1 1 2 Solution: vz = dz ⇒ q2 8 π ε0 m 11 − z d = q2 dt 8 π ε0 m dz =− dt 1 z...
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This document was uploaded on 03/19/2014 for the course EECS 6.641 at MIT.

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