Yb3 ya4005 yb4095 n3 molh 4 n4

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Unformatted text preview: mol/h 4 . n4 =120 mol/h Answers: A) yb3 = 0.53, yb5 = 0.63 B) yb3 = 0.53, yb5 = 0.15 C) yb3 = 0.47, yb5 = 0.63 D) yb3 = 0.47, yb5 = 0.15 Quiz #4 [email protected] First solve Stream 3: n3 = n1 + n2 = 200+ 100 = 300 mol/hr yb1n1 + yb2n2 = yb3n3 (0.5*200) + (0.4*100) = (yb3*300) 100 + 40= 300(ya3) à yb3 = 0.47 Next solve Stream 5: n5 = n3 – n4 = 300 -­‐ 120 = 180 mol/hr = ya3n3 = ya5n5 + ya4n4 (yb5*180) + (0.95*120) = (0.467*300) (yb5*180) + 114 = 140 à yb5 = 0.15 Ans: D) yb3 = 0.47, yb5 = 0.15...
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This test prep was uploaded on 04/03/2014 for the course CHME 2010 taught by Professor Tessier during the Fall '08 term at Rensselaer Polytechnic Institute.

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