# The bumpers were designed to deform elastically and

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Unformatted text preview: s were designed to deform elastically and spring back, i.e., to undergo low speed collisions without damage. Assuming the collision is elastic, what is the final speed of the truck? What impulse did the collision apply to the car? ---------------------------------------------------------------------------------------------Momentum is conserved. Also the speed of approach (2 m/s) is equal to the speed they recede from each other after the collision. Thus we write P total, originally equal to 1000*3 + 2000*1 = 5000N-sec and P final = 5000 = 1000v1 + 2000 v2 where v1 and v2 > v1 are the final velocities of the two vehicles. We also write v2 – v1 = 2 being the speed with which they recede from each other. Solving these two equations gives v2 = 2.33 m/s and v1 = 0.333 m/s The car changed its momentum from 3000 N-s to 333 N-s. Thus it received an impulse of -2666 N-s. The truck received an impulse of +2666N-s....
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## This note was uploaded on 04/01/2014 for the course PHYS 211 taught by Professor Tonyliss during the Spring '09 term at University of Illinois, Urbana Champaign.

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