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cs31 lecture 5

For i in 1vsize 1 do 2 for j in i1vsize do for 3 iff

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Unformatted text preview: easing order) 1. for i in 1..v.size-1 do 2. for j in i+1..v.size do for 3. iff v[i] > v[j] then i 4. tmp := v[j] tmp 5. v[j] := v[i] v[j] 6. v[i] := tmp v[i] 7. endif endif 8. endfor endfor 9. endfor 8 More on for loops x for <iterator> in <lb>..<ub> do Uses only one iterator, which is an integer counter lb and ub defines the range of values this iterator takes Without further argument, it increments by step of 1 for i in 1..10 step 2 => increments by step of 2 x Can be used to scan a set Example: Example: for i in SetA do for 9 While loops x Syntax: while <condition> do <instructions> <instructions> done x In English: “while the condition is true, do the block of In instructions” instructions” x Example: while (i <= 10) do print i print i := i + 1 := done 10 Differences between while loops and for loops x There is no assumption of a loop iterator with while loops x If you use one, the increment must be done explicitly x If the condition of the while loop relates to a loop iterator, If then it can be easily transformed into a while loop then x In general, while loops are less constrained, but requires In more information by the user more 11 Example: keyboard input x Problem: read a number from the user, with a guarantee Problem: that it is an integer number that Algorithm ReadInt: Output: • i: integer number typed by the user 1. str := readFromKeyboard() 2. while (not isInteger(str)) do 3. str := readFromKeyboard() str 4. done 5. return convertStrToInt(str) 12 Do loops x Syntax: do <instructions> <instructions> while <condition> x In English: “do the block of instructions while the In condition is true” condition x Example: do do print i print i := i + 1 := while (i <= 10) while 13 Example: keyboard input x Problem: read a number from the user, with a guarantee Problem: that it is an integer numb...
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