Unformatted text preview: ibitor is removed, then the following changes result: • Vmax’ would increase, as Vmax’ = Vmax/α. So, as [I] decreases, Vmax’ increases. • KM is unchanged, as it is unaffected by the presence or absence of inhibitor. Therefore, the effects on the plot would be: • y intercept increases because Vmax’ increases • slope is unchanged • x intercept increases also, since Vmax’ increases Doubling of [E]0 (green triangles) Since Vmax = k2[E]0, doubling [E]0 results in a doubling of Vmax’ without any impact on KM. Therefore, the effects of this doubling of enzyme concentration are identical to that from when the inhibitor is removed, as above. Non competitive inhibitor plot...
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 Fall '
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 Physical chemistry, pH, vmax

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