chem160.problemset11.answers

So as i decreases vmax increases km is unchanged as

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Unformatted text preview: ns Eadie- Hofstree plot (with competitive inhibitor present) • Vmax is unchanged so the y- intercept stays the same. • KM is larger, which results in two things: o x- intercept is smaller, as x- intercept = Vmax/KM’ o slope is larger, as slope = - KM’, so the line is steeper. The red data points correspond to values reflecting the presence of inhibitor. The blue data points correspond to the original kinetic data in Problem 1. Eadie- Hofstree plot 2.5 v0 2 1.5 1 0.5 0 0 0.2 0.4 0.6 0.8 1 1.2 1.4 1.6 v0/[ATP]0 Chemistry 160 problem set 11 solutions 3. The first plot is for a non- competitive inhibitor, and, based on the parameters of the x- and y- axes, this is clearly an Eadie- Hofstree plot. Thus, the parameters are as follows: • y- intercept = Vmax’ • slope = - KM • x- intercept = Vmax’/KM Removal of inhibitor (red squares) If the inh...
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This document was uploaded on 03/22/2014 for the course CHEM 160 at San Jose State University .

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