chem160.problemset11.answers

The blue data points correspond to the original

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Unformatted text preview: urve appears “shallower” with a less- steep climb to the asymptotic limit. The red data points correspond to the new KM’. You can see it takes a significantly higher [ATP]0 for the data to eventually reach Vmax in the presence of an inhibitor. Direct plot 2.5 v0 (uM/s) 2 1.5 1 0.5 0 0 10 20 30 40 50 60 [ATP]0 (uM) Chemistry 160 problem set 11 solutions Lineweaver- Burk plot (with competitive inhibitor present) • Vmax is unchanged so the y- intercept stays the same. • KM’ is larger, which results in two things: o x- intercept is smaller, as x- intercept = - 1/KM’ o slope is larger, as slope = KM’/Vmax, so the line is steeper. The red data points correspond to values reflecting the presence of inhibitor. The blue data points correspond to the original kinetic data in Problem 1. Lineweaver- Burk plot 2.5 2 1/v0 1.5 1 0.5 0 - 1 - 0.5 0 0.5 1 1.5 2 1/[ATP]0 Chemistry 160 problem set 11 solutio...
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This document was uploaded on 03/22/2014 for the course CHEM 160 at San Jose State.

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