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Unformatted text preview: vmax/KM. Eadie Hofstree plot 2.5 v0 2 1.5 1 0.5 0 0 0.2 0.4 0.6 0.8 1 1.2 1.4 1.6 v0/[ATP]0 Performing linear regression on the data in the plot results in the following data: y intercept = 2.30 therefore Vmax = 2.30 µM/s slope =  1.10 therefore, KM =  ( 1.10) = 1.10 µM Chemistry 160 problem set 11 solutions 2. If an competitive inhibitor is present, then the following happens to Vmax and KM. • Vmax remains the same • KM will become larger as it is converted to KM’, since KM’ is linearly correlated to [I], so, as [I] increases, KM’ also increases. KM’ = KM(1 + [I]/KI) = 1.10 µM x (1 + 80 nM/20 nM) = 5.50 µM Therefore, the effects on the plots are as follows: Direct plot • Vmax is unchanged, so the asymptotic limit remains the same at 2.30 µM/s • KM becomes larger, so this will affect the x value at half Vmax. Thus, the c...
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