Unformatted text preview: have that � � � � for a binary tree and any with � � . Thus, � �
tree is strongly ���� �separable, meaning that it can be cut exactly in half by cutting � � �
�
��
�� � ����� � � � � ������ � . So the binary tree can be cut in Now, we consider the constants. We have that � �
� half by cutting at most ������ � � �� edges. We can compute the appropriate constants by changing the base of the ���. � nodes,
�� �
Lemma 6Given a binary tree with � nodes and an input � , with � � � � �, there is a cut of a single edge that cuts off
between � �� and � nodes.
For a binary tree, there is also a simple more direct 4 approach. Basically, i claim that for any binary tree with
and a given number , with � , I can cut off a subtree with between � and nodes with a single cut. � �� Proof. Consider the depth (distance from root) of every node in the tree. Iterate through all the nodes i...
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 Spring '07
 BradleyKuszmaul
 Graph Theory, vlsi layout

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