Tutorial 12 - Project Management (Extra) Student

# Considerthecriticalpath possible paths time weeks a d

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Unformatted text preview: mber of Activities Subject to: (Used when crashing problem) Precedence relationship (Format: ES for the following activity ≥ EF for the required activity) 0 (____________) XA Xstart + 0 ‐> XA – Xstart 0 (____________) XB Xstart + 0 ‐> XB – Xstart 0 (____________) ‐> XC – Xstart XC Xstart + 0 3 (____________) XD XA + (3 ‐ YA) ‐> XD – XA + YA 2 (____________) ‐> XE – XB + YB XE XB + (2 ‐ YB) 1 (____________) XF XC + (1 ‐ YC) ‐> XF – XC + Yc 7 (____________) ‐> XG – XD + YD XG XD + (7 – YD) 6 (____________) XG XE + (6 – YE) ‐> XG – XE + YE ‐> Xfinish – XG +YG 4 (____________) Xfinish XG + (4 – YG) ‐> Xfinish – XF + YF 2 (____________) Xfinish XF + (2 – YF) Activity Crash Time Limit: YA ___; YB ___; YC ___; YD ___; YE ___; YF ___; YG ___ (Maximum time reduced for each activity) (Our objective) Project Completion: Xfinish ___________ Non‐Negativity: All X, Y ≥ 0 CB2201 Sem B in 2012/2013 – TA1, TA3, TA4, TB5, TC4, TF4, TE3, TE4, TE5, TF1, and TF3 *Reference: Crash the project manually (May be asked…I don’t know…) I. Consider the Critical Path: Possible Paths Time (Weeks) A-D-G 3+7+4=14* B-E-G 2+6+4=12 C-F 1+2=3 The Critical Path is A‐D‐G and the project completion time is 14 weeks. II. Crash the Critical Activity which has the lowest “Crash Cost per week” Activity A B C D E F G Immediate Predecessors A B C D,E Normal...
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