This preview shows page 1. Sign up to view the full content.
Unformatted text preview: ty similar to the one obtained in
the RC circuit. And the solution is nearly identical.
EE 442 RC and RL transients – 19 diL
dt
=
IS − iL
L/R
t
iL ( t )
dt
diL
=
I S − iL
0 L/R
ILi
IL (t )
ln [IS − iL ]
=
ILi After some rearrangement: t
0 t
t
L/R
0 t
iL (t) = IS − (IS − ILi ) exp − L
/R Note the similarity to the capacitor equation. Replace voltages with
currents and RC with L/R, and they are identical.
EE 442 RC and RL transients – 20 The quantitative result matches the earlier qualitative argument exactly.
At t = 0: IL (t = 0) = ILi (= 0)
VL (t = 0) = 0 After a long time, (t → ∞ ) IL (t → ∞) = IS
VL (t → ∞) = 0
In between, the inductor current changes, in an exponential fashion, from
ILi to IS. The voltage jumps to an initial value and then decays
exponentially to zero. Since this all happens within a given timespan,
these are known as inductor transient effects. EE 442 RC and RL transients – 21 Plots of inductor current and voltage for a circuit with IS = 4 mA, ILi = 0, R
= 2.5 kΩ, R = 5 H (L/R = 2 ms). EE 442 RC and RL transients – 22 The RC and RL transient equations are so similar and apply to so many
different situations, that is worth memorizing them.
More importantly, in any case where a single capacitor or inductor is
being switched into or out of a circuit, it is probably easier to make the
“circuit ﬁt the analysis”. In other words, use the Thevenin or Norton
equivalent equivalent of the circuit attached to capacitor or inductor to
make the problem look exactly like the prototypes that we just studied. EE 442 RC and RL transients – 23...
View
Full
Document
This document was uploaded on 04/05/2014.
 Fall '09
 Volt

Click to edit the document details