{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

Homework 7 Solution

# 2ms4us 800 clock cycles and name lab section 3 02

This preview shows page 1. Sign up to view the full content.

This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: With a clock prescaler factor of 64, how long is the duration in clock cycles for a start bit, a data bit of value 1, a data bit of value 0, and an idle interval between those bits? Allow 0.2ms error margin, e.g. a start bit can be 3 ±0.2ms. Ans: Clock frequency with a prescaler of 64 = ((16*10^6)/64) = 250000Hz Time taken for one cycle = 1/250000 = 4us i)Duration of a start bit = 3ms/4us = 750 clock cycles Taking error into consideration the duration of the start bit can be any value between 3+0.2 = 3.2ms, 3.2ms/4us = 800 clock cycles and Name: Lab Section: 3- 0.2 = 2.8ms, 2.8ms/4us = 700 clock cycles ii)Duration of a data bit of value 1 = 2ms/4us = 500 clock cycles Taking error into consideration the duration of the data bit of value 1 can be between 2+0.2 = 2.2ms, 2.2ms/4us = 550 clock cycles and...
View Full Document

{[ snackBarMessage ]}

Ask a homework question - tutors are online