{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

Final Exam Solution

# Find an easier route to the endpoint this scheme

This preview shows page 1. Sign up to view the full content.

This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: al state. Find an easier route to the endpoint: This scheme involves three separate reversible processes which together make up the total reversible path from initial to final state. (5 points for breaking up into reversible processes, does not have to be these 3 specifically.) Process 1 is the isobaric heating of 1 mol of liquid water from ! = −10 ° to ! = 0 °. Process 2 is the isobaric and isothermal conversion of liquid water to ice. Process 3 is the isobaric cooling of ice from ! = 0 ° to ! = −10 °. For an isobaric process, !!!"# !" ! = ! and since all these processes are performed reversibly, = ! = ! . So ! = ! ln !! . For the equilibrium phase transition, = ! !"!!"#\$%& ! . So !"#\$%& ! ! + + ! ln ! ! 273 1 −6009 263 = 1 76.11 ln + + 1 37.24 ln 263 273 273 = 2.840 − 22.01 − 1.390 = −20.56 !! (5 points for adding ΔS of all processes, 15 points for the right forms of ΔS for each process, 10 points for plugging in correct numbers) !"!...
View Full Document

{[ snackBarMessage ]}