problem19_62

# University Physics with Modern Physics with Mastering Physics (11th Edition)

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19.62: a) b) The isobaric process doubles the temperature to 710 K, and this must be the temperature of the isothermal process. c) After the isothermal process, the oxygen is at its original volume but twice the original temperature, so the pressure is twice the original pressure, Pa.
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Unformatted text preview: 10 80 . 4 5 × d) Break the process into three steps. J; 738 K) K)(335 mol J 5 mol)(8.314 25 . ( o 1-= ⋅-=-= nRT W J; 1023 ) 693 )(. K 710 )( K mol J 5 mol)(8.314 250 . ( ) 2 1 ln( ) 2 ( ) (p ln o 2 1 2 = ⋅ = = = T nR p nRT W 0). d (because 3 = = V W Thus, J. 285 = W...
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