problem19_52

University Physics with Modern Physics with Mastering Physics (11th Edition)

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19.52: a) b) At constant temperature, the product pV is constant, so ( 29 L. 00 . 6 L) 5 . 1 ( ) ( Pa 10 2.50 Pa 10 1.00 2 1 1 2 4 5 = = = × × p p V V The final pressure is given as being the same as Pa. 10 5 . 2 4 2 3 × = = p p The final volume is the same as the initial volume, so K. 0 . 75 ) ( 1 3 1 3 = = p p T T c) Treating the gas as ideal, the work done in the first process is ) ln( ) ln( 2 1 1 1 1 2 p p V p V V nRT = × × × × = - Pa 10 2.50 Pa 10 1.00 ln ) m 10 Pa)(1.5 10 00 . 1 ( 4 5 3 3 5 J, 208 =
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Unformatted text preview: keeping an extra figure. For the second process, )) ( 1 ( ) ( ) ( 2 1 1 2 2 1 2 2 3 2 p p V p V V P V V p-=-=-J. 113 Pa 10 2.50 Pa 10 00 . 1 1 ) m 10 Pa)(1.5 10 50 . 2 ( 4 5 3 3 4-= - =-The total work done is J. 95 J 113 J 208 =-d) Heat at constant volume....
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This document was uploaded on 02/06/2008.

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